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Physics Homework Help?
A 22-kg child starts from rest and slides down a slide that is 2.5 m high. At the bottom of the slide, the child is moving 1.91 m/s.
How much work, in joules, was done by the nonconservative force of friction on the child?
1 Answer
- AshLv 75 days ago
Initial Potential energy = Kinetic energy at the bottom + Work due to friction
Work due to friction = PE - KE
W(fr) = mgh - ½mv²
W(fr) = m(gh -½ v²)
W(fr) = (22 kg)[(9.81 m/s²)(2.5 m) - ½ (1.91 m/s)²]
W(fr) = 499 J
