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The perimeter of a rectangle is 52 m. Double the width is 7 m more than the length. Find the dimensions using a system of linear equations?
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- L. E. GantLv 75 days ago
2w + 2l = 52
2w = l+7
==> 3l+7 = 32
==> 3l = 45
==> l = 15
2w = l+7
==> 2w = 22
==> w = 11
so rectangle is 15 m by 11 m
- az_lenderLv 75 days ago
2L + 2W = 52;
2W - L = 7.
Subtract the 2nd eqn from the first and you get
3L = 45, so L = 15 and W = 11.
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