calired67

6x+10-x=2x+11-4

x=1?

Solve by completing the square

x^2-5x-3=0

I should know this too. but I have no idea

Solve equation by factoring

x(6x+19)=15

I should know how to do this but am soooooo lost right now.

not sure how to put square root so bear with me.

3a+1

_____

sq.root 3a+1

please help I am old and lost, explain as much as possible

The problem is 3a+1 over the square root of 3a+1

Multiplying and dividing rational expressions

10r^2st^3 3r^3t . 2s^3t^4

--------------- x -------- x -------------

6rs^2 2rst . 5s^2t^4

Please be as detailed as possible

ab+b+2a+2

__________

ab+a+b+1

Please be as detailed as possible.

I am soooo lost Please help!!!...This is a system of equations with 3 variables.

4x + 3z =4

2y - 6z =-1

3x +4y 3z =9

I have the answers just can't figure out how they got there.

(3/4,1/2,1/3)

Writng out two million in spanish?

dos millones or dos millónes

Write the equation of the line that passes through the given point and is perpendicular to the given line. Write the answer in slope intercept form

(1, - 5), x= -3/4y + 5

I am so #@%## lost!!

|x - 21| = - 8

Is this a no solution problem? Because of the -8 and absolute value having to be positive?

who was the guy in the bible that sang the scriptures and lead a good life but was told to get into heaven that he had to accept jesus Christ as his savior? I am sure that I heard this and need to locate it for a debate class

I don't know how to write absoulute value on here. So I will just put an ! on both sides. The book says the answer is No Solution, Can someone explain why?

!7/2x+3! = -5

5/2(7x - 15) + x is greater than or equal to 13/2x - 3/2

Not sure how to write it except this way > =

Simplify Complex Fraction( I know what the answer is I just can't figure out how they got to it) x over x+2 Over x over x+2 Plus x over 1

x

___

x+2

_____

x + x

___ _____

x+2 + 1

2a^3 - 16

__________

2a^2+ 4a+ 8

Please don't just give answer that I have. I am just lost somewhere in the factoring

Please explain as much as possible. Just giving me the answer won't help me. Thanks!!!