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Brennan Dai
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How do I calculate excess reagent?
FeS(s)+2HCl(aq)→FeCl2(s)+H2S(g)
A reaction mixture initially contains 0.236 mol FeS and 0.664 mol HCl.
Once the reaction has occurred as completely as possible, what amount (in moles) of the excess reactant is left?
My original thought was 0.096 moles because 0.664/2 - 0.236 is 0.096, but this isn't right. What am I doing wrong?
The answer and original values are given in moles.
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