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hustolemyname
Mainly answering maths questions to jog my memory of what I did years ago. I tend to add as contacts people that I see taking trouble to choose best answers.
real continued fraction has complex value?
let x be the continued fraction [1;-1]
1 - 1/( 1 - 1/( 1- 1/(1 - .... )))
if x = 1 - 1/x then x^2 = x - 1 so (x-1/2)^2 = -3/4
so x = (1+isqrt(3))/2
so 1 - 1/( 1 - 1/( 1- 1/(1 - .... ))) = (1+isqrt(3))/2
is there a fallacy in the working, or is that a genuine answer?
3 AnswersMathematics1 decade agois answers working?
everything seems frozen about 11 hours ago
2 AnswersOther - Yahoo Products1 decade agonegative skew?
suggestions please for parameterised distributions that I can try to fit something to ... like a normal curve with the summit pulled a little to the right with "endpoints" fixed.. i.e. gradually rising on the left, falling more sharply on the right.
1 AnswerMathematics1 decade ago2^x = x^2 supplementary?
x=2 : 2^2 = 4 = 2^2
x=4 : 2^4 = 16 = 4^2
are both solutions
why can't I see them as zeros in graph of xln(2) - 2ln(x) ?
4 AnswersMathematics1 decade agoAxiom of choice?
I was trying to explain to a child in non-mathematical terms why the axiom of choice was not straightforward.
I said - choose a real number. It will take you infinitely long to inspect it and know precisely which number you choose and distinguish it from neighbours that might only differ from it in the Nth decimal point. If you dont know what number you chose its rather meaningless to say you did actually choose one.
Can you improve on that?
1 AnswerMathematics1 decade ago