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2^x = x^2 supplementary?

x=2 : 2^2 = 4 = 2^2

x=4 : 2^4 = 16 = 4^2

are both solutions

why can't I see them as zeros in graph of xln(2) - 2ln(x) ?

Update:

duh ... I had x*ln(2)-2^ln(x) in excel!

but corrected now, and I dont see any smell of a zero other than 2 or 4

4 Answers

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  • Dr D
    Lv 7
    1 decade ago
    Favorite Answer

    Maybe it's because you didn't draw the graph.

    For x < 2, the function x*ln(2) - 2*ln(x) is positive

    For x > 4, it is positive again

    for 2 < x < 4, the function is negative.

    You should see them as zeros in the graph.

  • Anonymous
    1 decade ago

    Because you're not graphing it right?

    x=2 → 2ln2 - 2ln2 = 0.

    x=4 → 4ln2 - 2ln4 = ln(2^4 / 4^2)

    = ln(16/16) = ln1 = 0.

  • tom
    Lv 5
    1 decade ago

    On my graph plotter, I can...

    Perhaps you need to change the window/resolution of whatever you are graphing with.

  • 1 decade ago

    Yes you do!

    So did I!

    Try it again.

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