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Joel
Simple algebra question (and it's not homework)?
Can one of you clever people please help solve this equation for f? Assume x, y, and K are real number constants if that helps, but it's fine to leave them as variables. And no, it's not a graded schoolwork problem of any sort.
1 AnswerMathematics6 months agoPlease explain medical term "clinical reaction". Online reference would be nice.?
Our doctor used the term "clinical reaction", but did not provide a clear explanation. A web search shows this is a very common term, but I cannot find a definition, even in the online medical terminology dictionaries. Can anyone provide a concise explanation of the term and possibly provide the URL of a site supporting this definition? Thanks!
1 AnswerOther - Health1 decade agoIntegral of 1/[2r^2(r^2 + 1)]?
This is part of a bigger problem, but I hope you can please help me solve the integral of 1/[2r^2(r^2 + 1)], especially over the interval from negative ∞ to positive ∞. Thanks in advance!
1 AnswerMathematics1 decade agoIntegral of cos^2(Φ) dΦ over interval 0 to 2π?
This is part of a bigger problem, but I hope you can please help me solve the integral of cos^2(Φ) dΦ, especially over the interval 0 to 2π. Thanks in advance!
3 AnswersMathematics1 decade agoHow do I integrate Cos x Sin x dx?
How do I integrate Cos x Sin x dx? I'm working on an engineering problem and having trouble getting up to speed with simple integral calculus. Any help is much appreciated!
13 AnswersMathematics1 decade agoHelp with derivative, please? d/dx((x^2+2x+66)^1/2)?
This is not a "please do my homework for me" question. Actually, it's "please help me remember how to do differentiation so I can get on with my vector parabola minima work".
Help with derivative, please: d/dx((x^2+2x+66)^1/2)? Thanks!
1 AnswerMathematics1 decade agoCan you please help with Z^4 + Z^2 = 1/4? Answer: Z=+/- 0.455?
Can you please help with steps to solve Z^4 + Z^2 = 1/4? Answer: Z=+/- 0.455, but how is it solved? I'm drawing a blank. No, this is not a homework problem, but rather self-study. Thanks!
9 AnswersMathematics1 decade ago