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Favorite Answer
conversion of an int to a string in c++, using a stringstream object :
method 1:
#include <iostream>
#include <sstream> // Required for stringstreams
#include <string>
std::string IntToString ( int number )
{
std::ostringstream oss;
// Works just like cout
oss<< number;
// Return the underlying string
return oss.str();
}
int main()
{
int number = 12345;
std::string result = IntToString ( number );
// Now we can use concatenation on the number!
std::cout<<"~~{" + result + "}~~\n";
}
method 2 : it will display as true r false
#include <sstream>
#include <string>
using namespace std;
bool StringToInt(const string &s, int &i);
int main(void)
{
string s1 = "12";
string s2 = "ZZZ";
int result;
if (StringToInt(s1, result))
{
cout << "The string value is " << s1
<< " and the int value is " << result << endl;
}
else
{
cout << "Number conversion failed" <<endl;
}
if (StringToInt(s2, result))
{
cout << "The string value is " << s2
<< " and the int value is " << result << endl;
}
else
{
cout << "Number conversion failed on " <<s2 <<endl;
}
return(0);
}
bool StringToInt(const string &s, int &i)
{
istringstream myStream(s);
if (myStream>>i)
return true;
else
return false;
/*
* Program output:
The string value is 12 and the int value is 12
Number conversion failed on ZZZ
*
*/
method 3 : The simpest method of all
#include<iostream>
#include<string>
#include<sstream>
using namespace std;
string itos(int i)// convert int to string
{
stringstream s;
s << i;
return s.str();
}
int main()
{
int i = 127;
string ss = itos(i);
const char* p = ss.c_str();
cout << ss << " " << p << "\n";
}
KillingJoke
#include<stdlib.h>
...
for integer
itoa(int n,char* s);
for long
ltoa(long int n, char*s);