I really need help with this algebra question? Please!!!!!?
Sheilds and jim sold tickets to the b-ball games. Good seats were $5 each and bad were $2 each. 210 people attended and $660 was paid how many people bought good seats.
Sheilds and jim sold tickets to the b-ball games. Good seats were $5 each and bad were $2 each. 210 people attended and $660 was paid how many people bought good seats.
John F
Favorite Answer
x = number of good seats sold
y = number of bad seats sold
5 dollars for one good seat means 5x dollars for x
good seats
2 dollars for one bad seat means 2y dollars for y
bad seats
=>
x + y = 210
5x + 2y = 660
<=>
x + y = 210
5x + 2 * (210 - x) = 660
<=>
x + y = 210
5x - 2x + 420 = 660
<=>
x + y = 210
3x = 240
<=>
x + y = 210
x = 80
<=>
x = 80
and
y = 210 - 80 = 130
Answer :
80 good seats
and
130 bad seats
*******
Robert S
x = 2 dollar tickets
y = 5 dollar tickets
x + y = 210
2x + 5y = 660
y = 210 -x (solving first equation for y)
2x + 5(210 - x) = 660 (substituting in for y)
2x + 1050 - 5x = 660 (distributive property)
-3x + 1050 = 660 (combinign like terms)
-3x = -390 (subtracting 1050 from both sides)
x = 130 (dividing both sides by -3)
Now substitute into the original equation..
130 + y = 210
y = 80 (subtracting 130 from both sides)
They sold 80 good seats.
grean
Use what you know and break everything down.
5 dollar seats and 2 dollar seats.
210 people
$660 total.
Use x and y's and create 2 equations.
5x+2y=660
x+y=210
3x=240
x=80
y=130
and now answer the final question.
april29jc
let x = the good seats ($5)
let y = bad seats ($2)
formulas:
x+y = 210
5x + 2y = 660
use substitution to solve for x and y.