I really need help with this algebra question? Please!!!!!?

Sheilds and jim sold tickets to the b-ball games. Good seats were $5 each and bad were $2 each. 210 people attended and $660 was paid how many people bought good seats.

John F2009-04-16T17:41:15Z

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x = number of good seats sold

y = number of bad seats sold

5 dollars for one good seat means 5x dollars for x

good seats

2 dollars for one bad seat means 2y dollars for y

bad seats

=>

x + y = 210

5x + 2y = 660

<=>

x + y = 210

5x + 2 * (210 - x) = 660

<=>

x + y = 210

5x - 2x + 420 = 660

<=>

x + y = 210

3x = 240

<=>

x + y = 210

x = 80

<=>

x = 80

and

y = 210 - 80 = 130


Answer :

80 good seats

and

130 bad seats

*******

Robert S2009-04-17T00:46:51Z

x = 2 dollar tickets
y = 5 dollar tickets

x + y = 210
2x + 5y = 660

y = 210 -x (solving first equation for y)

2x + 5(210 - x) = 660 (substituting in for y)

2x + 1050 - 5x = 660 (distributive property)

-3x + 1050 = 660 (combinign like terms)

-3x = -390 (subtracting 1050 from both sides)

x = 130 (dividing both sides by -3)

Now substitute into the original equation..

130 + y = 210

y = 80 (subtracting 130 from both sides)

They sold 80 good seats.

grean2009-04-17T00:41:50Z

Use what you know and break everything down.
5 dollar seats and 2 dollar seats.
210 people
$660 total.

Use x and y's and create 2 equations.
5x+2y=660
x+y=210

3x=240
x=80
y=130

and now answer the final question.

april29jc2009-04-17T00:41:23Z

let x = the good seats ($5)
let y = bad seats ($2)

formulas:

x+y = 210
5x + 2y = 660

use substitution to solve for x and y.