I really need help with this algebra question? Please!!!!!?

x = number of good seats sold

y = number of bad seats sold

5 dollars for one good seat means 5x dollars for x

good seats

2 dollars for one bad seat means 2y dollars for y

bad seats

=>

x + y = 210

5x + 2y = 660

<=>

x + y = 210

5x + 2 * (210 - x) = 660

<=>

x + y = 210

5x - 2x + 420 = 660

<=>

x + y = 210

3x = 240

<=>

x + y = 210

x = 80

<=>

x = 80

and

y = 210 - 80 = 130

Answer :

80 good seats

and

130 bad seats

*******

x = 2 dollar tickets

y = 5 dollar tickets

x + y = 210

2x + 5y = 660

y = 210 -x (solving first equation for y)

2x + 5(210 - x) = 660 (substituting in for y)

2x + 1050 - 5x = 660 (distributive property)

-3x + 1050 = 660 (combinign like terms)

-3x = -390 (subtracting 1050 from both sides)

x = 130 (dividing both sides by -3)

Now substitute into the original equation..

130 + y = 210

y = 80 (subtracting 130 from both sides)

They sold 80 good seats.

Use what you know and break everything down.

5 dollar seats and 2 dollar seats.

210 people

$660 total.

Use x and y's and create 2 equations.

5x+2y=660

x+y=210

3x=240

x=80

y=130

and now answer the final question.

let x = the good seats ($5)

let y = bad seats ($2)

formulas:

x+y = 210

5x + 2y = 660

use substitution to solve for x and y.