I need some help with math, how do you do these problems?

8√54 - 4√6

2√24 + 4√54 + 5√96

what are the answers to these two problems, and how did you solve them.. Thank-you

Curtis Strangelove III2009-12-02T18:22:19Z

Favorite Answer

8√54 - 4√6 = 24√6 - 4√6 = 20√6

2√24 + 4√54 + 5√96 = 2√24 + 12√6 + 10√24 = 4√6 + 12√6 + 20√6 = 36√6

Ms. Worth2009-12-02T18:30:06Z

You can't add or subtract these terms unless they are "like" terms In this case, that means that the numbers under the square root sign have to be the same.

Example:
Cannot add:
2√6 + 3√5

Can add:
2√6 + 3√= 5√6

So to solve the problems you have, factor the numbers under the square root sign to find any perfect squares. Once you bring the square roots of the perfect squares to the outside, the numbers that are left might be like terms with the other terms.

Add 8√54 - 4√6

Step One: Factor
8√9x6 - 4√6

Step Two: Bring the square root of 9 to the outside
(3x8)√6 - 4√6
24√6 - 4√6

Step Three: Combine like terms
20√6
-------------------------------------
Add 2√24 + 4√54 + 5√96

Step One: Factor to find any perfect squares
2√4x6 + 4√9x6 + 5√16x6

Step Two: Bring the square roots to the outside
(2x2)√6 + (3x4)√6 + (4x5)√6
4√6 + 12√6 + 20√6

Step Three: Add like terms
36√6

?2009-12-02T18:20:36Z

1. 54=6*9=2*3^2. Take the 3 out. Then simplify by rationalizing the denominators. GO!

Anonymous2009-12-02T18:21:16Z

Use your calculator to find the square roots

8 times square root of 54 , then subtract 4 times the square root of 6

etc.

?2009-12-02T18:24:00Z

8x3√6-4√6
24√6-4√6
20√6

2x2√6+4x3√6+5x4√6
4√6+12√6+20√6
36√6