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I need some help with math, how do you do these problems?

8√54 - 4√6

2√24 + 4√54 + 5√96

what are the answers to these two problems, and how did you solve them.. Thank-you

5 Answers

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  • 1 decade ago
    Favorite Answer

    8√54 - 4√6 = 24√6 - 4√6 = 20√6

    2√24 + 4√54 + 5√96 = 2√24 + 12√6 + 10√24 = 4√6 + 12√6 + 20√6 = 36√6

  • 1 decade ago

    You can't add or subtract these terms unless they are "like" terms In this case, that means that the numbers under the square root sign have to be the same.

    Example:

    Cannot add:

    2√6 + 3√5

    Can add:

    2√6 + 3√= 5√6

    So to solve the problems you have, factor the numbers under the square root sign to find any perfect squares. Once you bring the square roots of the perfect squares to the outside, the numbers that are left might be like terms with the other terms.

    Add 8√54 - 4√6

    Step One: Factor

    8√9x6 - 4√6

    Step Two: Bring the square root of 9 to the outside

    (3x8)√6 - 4√6

    24√6 - 4√6

    Step Three: Combine like terms

    20√6

    -------------------------------------

    Add 2√24 + 4√54 + 5√96

    Step One: Factor to find any perfect squares

    2√4x6 + 4√9x6 + 5√16x6

    Step Two: Bring the square roots to the outside

    (2x2)√6 + (3x4)√6 + (4x5)√6

    4√6 + 12√6 + 20√6

    Step Three: Add like terms

    36√6

  • 1 decade ago

    1. 54=6*9=2*3^2. Take the 3 out. Then simplify by rationalizing the denominators. GO!

  • Anonymous
    1 decade ago

    Use your calculator to find the square roots

    8 times square root of 54 , then subtract 4 times the square root of 6

    etc.

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  • 1 decade ago

    8x3√6-4√6

    24√6-4√6

    20√6

    2x2√6+4x3√6+5x4√6

    4√6+12√6+20√6

    36√6

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