Cartesian equation for a polar curve?
Hi,
How do you find the Cartesian equation for r=2sinθ (0<=θ<π)?
Many, many thanks,
Froskoy.
Hi,
How do you find the Cartesian equation for r=2sinθ (0<=θ<π)?
Many, many thanks,
Froskoy.
phasor
Favorite Answer
r=√(x²+y²)
Θ=tan(-1)y/x
r=2sinθ
√(x²+y²=2sin(tan(-1)(y/x))
√(x²+y²=2y/√(x²+y²)
x²+y²=2y
(y-1)²+x²=1
the restriction (0<=θ<π) means only once around the circle so the equation is correct as is.