Physics question, grade 11 level, 10 points for best answer?
Hey, I've been having some trouble with my physics homework, could anybody help me and explain step by step?
the formulas are: a = (Vf –Vi)/t d = Vit + (at^2)/2 Vf^2 = Vi^2 + 2ad
A toy rocket is thrown upwards off a platform that is 34.3m high, with a velocity of 29.4m/s. a) Find the time necessary to reach the rocket's maximum height b) Find the time it will take before the rocket reaches the ground c) Find the velocity of the rocket when it hits the ground
thanks :)
Hugh2010-02-23T23:57:06Z
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Select the positive direction as downward. Then a=g, Vi=-29.4 m/s. a) At the maximum height, the velocity Vf=0. From g = (Vf - Vi)/t t = (Vf - Vi)/g t = (0 - (-29.4))/9.8 t = 3 sec b) The time it takes to reach the ground is from d = Vi*t + a*t^2 with d=34.3, Vi=-29.4 and solve for t. t = 7 sec. c) Use Vf^2 = Vi^2 + 2gd with Vi=-29.4, g=9.8, d=34.3 Vf = sqrt(29.4^2 + 2*9.8*34.3) Vf = 39.2 m/s
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