Physics question, grade 11 level, 10 points for best answer?

Select the positive direction as downward. Then a=g, Vi=-29.4 m/s.

a) At the maximum height, the velocity Vf=0.

From g = (Vf - Vi)/t

t = (Vf - Vi)/g

t = (0 - (-29.4))/9.8

t = 3 sec

b) The time it takes to reach the ground is from

d = Vi*t + a*t^2

with d=34.3, Vi=-29.4 and solve for t.

t = 7 sec.

c) Use Vf^2 = Vi^2 + 2gd

with Vi=-29.4, g=9.8, d=34.3

Vf = sqrt(29.4^2 + 2*9.8*34.3)

Vf = 39.2 m/s

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