Given that E_cal = 9.0 V, R = 170 \Omega and C = 25 \mu F, how much charge is on the capacitor at time t = 4.4?

Question

The switch on an RC circuit is closed at t = 0. Given that E_cal = 9.0 V, R = 170 &#92;Omega and C = 25 &#92;mu F, how much charge is on the capacitor at time t = 4.4 ms?

DH · Accepted Answer

v = V0*(1 - e^(-t/RC)) 

= 9.0*(1 - e^(-4.4x10^-3/(170*25x10^-6)) = 5.80V

Given that E_cal = 9.0 V, R = 170 \Omega and C = 25 \mu F, how much charge is on the capacitor at time t = 4.4?

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