factoring on Ti 89 titanium?

I am trying to factor

9x^2+6x+4

When I do factor(9x^2+6x+4)

it gives me

9(x^2+.667x+.4444)

Thats fine and all but I want it to fully factor it all, how do I make it factor the (...) part?

Im also well aware that this is an irreducible factorization but I would like it in terms of i if at all possible. Sure makes Diff-Eq homework easier. Anyone help?

llaffer2014-03-07T10:58:11Z

That expression doesn't factor. The zeroes of that expression are imaginary.

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JOS J2014-03-07T10:57:23Z

(x - 1/3 (1 + i Sqrt[3])) (x - 1/3 (1 - i Sqrt[3]))

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wana bigger bike2014-03-07T11:05:38Z

It does factor you just use "I" for the imaginarys. Otherwise idk how to do this diff eq qork

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