Roger the Mole
Favorite Answer
(333 g Al2(SO4)3·18H2O) / (666.4259 g Al2(SO4)3·18H2O/mol) × (18 mol H2O / 1 mol Al2(SO4)3·18H2O) ×
(6.022 × 10^23 molecules/mol) = 5.42 × 10^24 molecules H2O
Sheldon
18 x molec. wt. H20/molec. wt. Al2(SO4)3.18H2O x 33g= ?g H20
? g H2O/molec. wt H2O= ?moles H2O
?moles H2O x 6.02E-23 molecules/mole= ans.