How do you clear a radical from the denominator of a fraction?

This is called rationalizing the denominator. To do this you multiply the whole fraction by some form of 1, usually in the form of the radical you want to clear out.

Let's say you have 4/sqrt(5). To get rid of the sqrt(5) in the denominator you muliply by [sqrt(5)/sqrt(5)].

[(4/sqrt(5)] * [sqrt(5)/sqrt(5)]

= [4 sqrt(5)] / [sqrt(5)]^2

=[4 sqrt(5)] /5

by a process called racionalization. U multiply your expresion times a racionalized expresion of 1 (ex. √x/√x)

so will eliminate the root in the denominator. Follow this example for the expresion 3/√2:

(3/√2)*(1)=(3/√2)*(√2/√2)= (3√2)/2

ok so say u have 2 over the square root of 5, u would multiply that fraction by the square root of 5 over the square root of 5...so that would give u 2 times the square root of 5 and then all of that is over just 5. hope that makes sense

its its a monimial radical like x/sqrt(y) just multiply by itself top and bottom. if its binomial, like x/(sqrt(a)+sqrt(b)) multiply top and bottom by its conjugate sqrt(a)-sqrt(b). same thing with sqrt(a)+b since b=sqrt(b^2)

it helps if u actually post the original question