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stillborndesires01
stillborndesires01 asked in Science & MathematicsMathematics · 2 decades ago

solve inequality?

Solve the inequality in terms of intevals: 4x< 2x + 1 ≤ 3x + 2

Update:

Show work, please.

8 Answers

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  • prune
    2 decades ago
    Favorite Answer

    2x<1 , x<0.5

    -1<x

    -1< x<0.5

  • Don Pepe
    2 decades ago

    -1≤ x < 1/2

    Source(s): 4x<2x+1____ x<1/2: 2x+1≤ 3x+2 _______ -1≤ x por lo tanto -1≤ x < 1/2
  • Sherman81
    Lv 6
    2 decades ago

    4x < 2x + 1 <= 3x + 2

    4x < 2x + 1

    2x < 1

    x < (1/2)

    2x + 1 <= 3x + 2

    -x <= 1

    x >= -1

    -1 <= x < (1/2)

  • Aslan
    Lv 6
    2 decades ago

    subtract 2x from all parts of this inequality to get

    2x < 1 =< x +2

    Then we can break it down into further parts

    2x<1

    implies that x<1/2

    second part

    1=<x+2

    1-2=<x

    -1=<x

    so combining both parts we find that x lies in the band

    -1=<x<1/2

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  • Vivek
    Lv 4
    2 decades ago

    4x< 2x + 1 ≤ 3x + 2

    take this 1st: 4x< 2x + 1

    or 4x-2x< 1

    0r x<1/2

    now take anothe one

    2x + 1 ≤ 3x + 2

    or -x<1

    or x>-1

    hence -1<x<1/2

  • Anonymous
    2 decades ago

    2x-3x<2-1

    -x<-1

    X > 1

  • retard
    2 decades ago

    I cannot believe you guys are doing his homework..... sheesh

  • Anonymous
    5 years ago

    x=>-1

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