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math problem?

13

∫ 2xdx

10 ? ok what does it mean? it's not my homework (i'm 57 years old) i just want to know,? i forgot most of my calculus from not using it.

Update:

it didn't print out the way it looked when i wrote it...

the ten on the bottom and the thirteen on top by the integral sign, then 2xdx...

Update 2:

i thought it was 69 , it was on a college students t-shirt with a ?mark

6 Answers

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  • 1 decade ago
    Favorite Answer

    another person already solved it but ill explain it :)

    you need to take the antiderivative of 2x which in this case is x squared, then solve for x at 13.

    you get 169 << (thirteen squared)

    then you solve for x at 10.

    we get 100 (10 squared)

    subtract 100 from 169 and you get 69.

    Source(s): this link explains the fundamental theorem of calculus http://en.wikipedia.org/wiki/Fundamental_theorem_o...
  • Helmut
    Lv 7
    1 decade ago

    You got it right in 1!

    Integral(2xdx) = x^2 + C

    applying the limits:

    13^2 - 10^2 = 69

  • 1 decade ago

    13 and 10 are the upper and lower limits(respectively) of the integral.

    solving the integral gives x^2

    solving between the limits,

    13^2 - 10^2

    =169 - 100

    =69.

  • Anonymous
    1 decade ago

    13

    =[2x^2/2]

    10

    13

    =[x^2]

    10

    =13^2 - 10^2

    =(13+10)*(13-10)

    =23*3=69 ans

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  • 1 decade ago

    13

    =2*x^2/2]

    10

    13

    =x^2]

    10

    =13^2 - 10^2

    =169-100

    69

  • SAN
    Lv 5
    1 decade ago

    No doubt a geek reference to certain sexual activities college students are known to pursue.

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