balanced equation?

Assuming you really mean carbon monoxide and not dioxide then:

TiO2 (s) + 2C (s) + 2Cl2(g) TiCl4(s?) + 2CO(g)

Same number of each type of atom on each side. Start by looking at the highest number in this case 4 inTiCl4, it comes from Cl2 so need 2Cl2. Then O start with 2 so must end with 2 so 2CO so need 2C on the other side to provide the other carbon.

if you are producing carbon dioxide then:

TiO2 + C + 2Cl2 TiCl4 + CO2

Sorry am not sure of physical state of TiCl4. (s) indicates solid, (g) indicates gas, (aq) in aqueous solution, (l) liquid.

At a guess:

TiO2 + 2C + 2Cl2 --> TiCl4 + 2CO

C is a solid, Cl2 a gas (I think) and CO is definately a gas.

No clue about the other two. Why not look it up? You must have data tables or something.

TiO2 + 2C + 2CL2 =====> TiCl4 + 2CO

wow i haven't done this in ages i hope i'm right

TiO2 + 2C + 2Cl2 ---> TiCl4 + 2CO

TiO2 (s) + 2C (s) + 2Cl2 (g) -> TiCl4 (s) + 2CO (g)

that ones right:)

TiO2 (s) + 2C (s) +2Cl2 (g) --> TiCl4 (s) + 2CO (g)

TiO2 (s) + 2C (s) + 2Cl2 (g) -> TiCl4 (s) + 2CO (g)

mitch -

if you're doing your homework - i suggest you learn how in fact the answer is achieved. you will not benefit from just learning the final line.

v5g

c2ho5 or something like that