[(2a2 + a - 6)/(a2 +4a - 5)] · [(a3 - 3a2 + 2a)/(4a2 - 6a)] =?

2a^2+a-6=(2a-3)(a+2)

a^2+4a-5=(a+5)(a-1)

a^3-3a^2+2a=a(a-2)(a-1)

4a^2-6a=2a(2a-3)

using the rule (a/b)*(c/d)=ac/bd

(2a-3)(a+2)(a)(a-2)(a-1)/(a+5)(a-1)(2a)2a-3)

=(1/2)(a+2)/(a+5)

Use long division and the order of operations.

Parenthesis or brackets (first)

Exponents and radicals

Multiplication

Division

Addition

Subtraction

Okay, put each over the other like below. . .

2a^2 + a - 6Xa^3 - 3a^2 + 2a

a^2 + 4a - 5 a^2 -6 a

Subtract or add as you would in regular subtraction leaving :

(3a^2 + 5a - 11) X (a^3 - 2a^2 - 4a = ?

OR

a^3 + a^2 - a -11

start up with the aid of factoring all expressions: [(2a² + a - 6) / (a² + 4a - 5)] × [(a³ - 3a² + 2a) / (4a² - 6a) [(2a - 3)(a + 2) / (a + 5)(a - one million)] × [a(a² - 3a + 2) / 2a(2a - 3)] [(2a - 3)(a + 2) / (a + 5)(a - one million)] × [a(a - 2)(a - one million) / 2a(2a - 3)] [a(2a - 3)(a + 2)(a - 2)(a - one million)] / [2a(a + 5)(a - one million)(2a - 3)] [(a + 2)(a - 2)] / [2(a + 5)] [(x2 - x - 6) / (y2 + 3y - 10)] · [(y2 - 7y 10) / (3x2 x - 10)] ÷ [(x2 - 2x - 3) / (9x2 - 25)] = [(x - 3)(x + 2) / (y - 2)(y + 5)] × [(y - 2)(y - 5) / (3x - 5)(x + 2)] / [(x + one million)(x - 3) / (3x - 5)(3x + 5)] = [(x - 3)(x + 2) / (y - 2)(y + 5)] × [(y - 2)(y - 5) / (3x - 5)(x + 2)] × [(3x - 5)(3x + 5) / (x + one million)(x - 3)] = (x - 3)(x + 2)(y - 2)(y - 5)(3x - 5)(3x + 5) / (y - 2)(y + 5)(3x - 5)(x + 2)(x + one million)(x - 3) = (y - 5)(3x + 5) / (y + 5)(x + one million)

[(2a^2+ a-6)/(a^2+4a-5]x[(a^3-3a^2+2a)/(4a^2-6a)]

=[(2a-3) (a+2)/(a+5) (a-1)]x[ a (a-2)(a-1)/2a(2a-3)]

=[(a+2)/(a+5)]x[(a-2)/2]

=(a+2) (a-2)/[(a+5)x2]

=(a^2-4) /(2a+10)

start with factoing each poynomial

(2a-3)( a+2)/(a-1)(a+5)*a(a-1)(a-2)/2a(2a-3)

cross cancel leaving

(a+2)(a-2)/2(a+5)

Maybe you'll take a palmtop to the exam and keep asking yahoo questions during it? Cause if you don't do your homework (basic knowledge, nothing complicated!!!!!!!!!!!!!!!!!!), you won't pass any exam...

I believe it cancels out

you need to have one of the variables in here, unless you are trying to just simplify this.

(a²-4)/(2a+10)

ok first off all i really could answer this for you if I wanted but i ain't doing oyur homework sry