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squaring negitive binomials??
Im alright with squaring binomials but i ran across this problem and im lost.... -(3y-8)^2
I did this (-3y--8)^2
then (-3y +8)^2
so then (-3y)^2+(2*-3y*8)+8^2
So then 9^2 +(-48y)+ 64 for my answer
My book says the answer is -9y^2+48y-64
Um where did i go wrong??? Im totally lost on how to get the answer they said to get.... any help plzzzz!!! :) THanks bunches
2 Answers
- 1 decade agoFavorite Answer
Yup, that's wrong. You can't move the negative sign into the brackets. You need to expand the brackets, and THEN multiply the whole thing by -1.
- 1 decade ago
(-3y-(-8))^2 does not equal -(3y-8)^2.
Remember order of operations?
PEMDAS?
Parenthesis, then EXPONENTS, then MULTIPLICATION.
Expand the binomial, then multiply by negative 1.
