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What is X. X=e^(i*pi). ["e" raised to the ("i" times "pi")?
4 Answers
- modulo_functionLv 71 decade agoFavorite Answer
it's -1
e^(ix) = cos x + i*sin x, for real values of x, in radians.
so if x=pi, then this is cos pi which is -1.
- 1 decade ago
The Euler's identity is:
e^(i*n) = cos(n) + i*sen(n)
Switching pi for 'n', you have:
e^(i*pi) = cos(pi) + i*sen(pi) = -1 + i*0 = -1 => e^(i*pi) = -1
- Wal CLv 61 decade ago
As everyone above has stated:
e^(iÏ) = -1
In Maths week in New South Wales many years ago a very clever publicity sticker was released that stated:
"Maths teachers are # -e^(iÏ)"
Source(s): Me ;^))
