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classroom help plz can't write the whole thing hear?
A square has sides of length (w+5) units. If a rectangle with a length of (w+2) units and a width of (w-3) units is removed from the interior of the square, which of the following is the remaining area of the square?
2 Answers
- 1 decade agoFavorite Answer
first off lets get the area of the square
a=(w+5)(w+5)
=w^2+10w+25
now we get the area of the rectangle
r=(w+2)(w-3)
=w^2-w-6
and subtract the areas
a(remaining)=a-r
=(w^2+10w+25)-(w^2-w-6)
=11w+31
and that is the area that is left
- hayharbrLv 71 decade ago
Find the areas by multiplying out length times width by FOIL
(w+5)(w+5)
(w+2)(w-3)
Then subtract the second answer from the first. be sure to subtract all three terms; that is, change all three terms' signs before combining like terms.
