Algebra elimination?

Equations:

1. x + 2y = 8

2. 2x - y = 6

*Solve for "x" or "y" in either equation. Let's solve for "x" in the 1st equations.

First: subtract "2y" from both sides....

x + 2y - 2y = 8 - 2y

x = 8 - 2y

Sec: replace "8-2y" with the x-variable in the 2nd equation.....

2(8 - 2y) - y = 6

2(8) + 2(-2y) - y = 6

16 - 4y - y = 6

16 - 5y = 6

*Subtract "16" from both sides....

16 - 16 - 5y = 6 - 16

- 5y = - 10

*Isolate "y" on one side --- divide both terms by "-5"....

- 5y/-5 = - 10/-5

y = 10/5

y = 2

Third: replace "2" with the y-variable in the 1st equation.....

x + 2(2) = 8

x + 4 = 8

*Isolate "x" on one side --- subtract "4" from both sides...

x + 4 - 4 = 8 - 4

x = 4

Solution (4, 2)

You don't have two equations, but I will assume that the second set is supposed to be 2x-y=6.

The first equation can be rewritten to x=8-2y. This is plugged into the second equation which is 2(8-2y)-y=6. This becomes -5y=-10 or y=2. Plug that into the rewritten first equation and x=8-4=4.

you have mistaken the second equation. It is 2x - y = 6

x + 2y = 8 first equation

2x - y = 6 second equation multiplied by 2

4x - 2y = 12 second equation

x + 2y = 8 first equation (add first and second equation)

5x = 20

x = 20/5 = 4

take first equation

x + 2y = 8 (substituting the value of x=4)

4 + 2y =8

2y = 8 - 4

2y = 4

y = 2

x = 4; y = 2

1.x+2y=8

2. 2x-y=6 (I hope you meant =6 and not +6)

Let's solve for y first, since it's easier. In order to cancel out the y's, we have to make them opposites, so we multiply the 2nd equation by 2. This is what we get:

1. x+2y=8

2. 4x-2y=12

We can now cancel out the y's. Just add the x's and 8 and 12 now, and we get this:

5x=20

Solving for x, we get:

x=4

Now we plug the 4 back into either original equation. I'm choosing the 1st one, since it's easier.

4+2y=8

Now minus 4 from both sides to get y alone:

2y=4

Now divide the 2 from both sides to solve for y, and we get:

y=2

Therefore, your answers are x=4 and y=2.

x+2y=8....(1)

2x-y=6.....(2)

Multiplying eqn. 1 by 2 and eqn 1 by 1 we get

2x+4y=16

2x-y =6

subtracting 5y=10

=>y=2

putting the value of y in eqn no 1,we get

x+2*2=8

=>x+4=8

=>x=8-4=4

first solve for x in terms of y:

x+2y =8. x= 8-2y. Then plug this new definition of x into the 2nd equation.

Unfortunately your 2nd equation doesn't have an = sign, so something isn't right. But hope that helps.

allow s = type of strings w = type of winds The equations are s + w = ninety one 4s = 9w remedy for s. s = ninety one - w change in 4s = 9w 4(ninety one - w) = 9w 364 - 4w = 9w 364 = 13w w = 364/13 = 28 s = ninety one - w = ninety one - 28 = sixty 3 So the range of strings is sixty 3 and the range of winds is 28. in case you divide both one among those by technique of seven you'll stumble on you get the 9 to 4 ratio wanted.

x+2y=8

2x-y+6

Multiply the second equation by 2, so that when we add the y's cancel

x + 2y = 8

4x -2y = 12

---------------

5x = 20

x =4

so sub 4 in for x

4 + 2y = 8

2y = 4

y = 2

Multiply first equation by 2.

2x + 4y = 16

2x - y = 6

Subtract equations.

5 y = 10

y = 2

Substitute 2 for y in first equation.

x + 4 = 8

x = 4

There's no = sign in the second expression, so there's no way to "solve" this. Unless that was a typo.