system of equation?

6x-90+3y

x-3y=50

I think that you mistyped the question (no equals sign in the first equation.) I hope that I have guessed the equation correctly; if not, let me know the correct equations & I'll redo it.

6x-90=3y

x-3y=50

This is most easily solved by substitution.

x-(6x-90)=50 - Plug the first equation in for the 3y value in the second equation.

Now, simplify & solve for x.

x-(6x-90)=50

-5x -90 = 50

-5x -90 +90 = 50 +90

-5x = 140

-5x / -5 = 140 / -5

x = -28 - Plug this value into either of the original equations & solve for y.

x-3y=50

(-28) - 3y = 50

(-28) - 3y + 28 = 50 + 28

-3y = 78

-3y / -3 = 78 / -3

y = -26

*********************Update****************

Based on the new equations...

6x=90+3y

If you move the 90 to the other side of the equation, you get:

6x - 90 = 90 + 3y - 90

6x - 90 = 3y which is the same as my presumed equation, os my solution should work for you.

use substitution:

x=50-3y

Insert new equation for x into the first equation

6(50-3y)-90+3y=0

300-18y-90+3y=0

210-15y=0

-15y=-210

y=14

Back to the second equation:

x-3(14)=50

x-42=50

x=92

Solution is:

x=92, y=14

you have to use substituition:

x=3y+50

6(3y+50)-90+3y

18y+300-90+3y

21y+210

21y=-210

y=-10

then you have to plug y into x=3y+50

x=3(-10)+50

x=-30+50

x=20

so y=-10, x=20

Hi, you left out an equal sign in the first one; can you retype it and re-submit? Then someone will help you.