help with Solving Equalities and equations!! Please!!?

let x be the length. let y be the width.

Therefore,

2x + 2y = 38

which means that x + y is 19

x is 3y - 1, so substitute that in to get

3y - 1 + y = 19

4y = 20

y = 5, then x is 14

A rectangle has four sides. There are two pairs of sides of equal measure called length (L) and width (W).

Therefore the perimeter = L + L + W + W = 38

So: 2*L + 2*W = 38

We are given that L = 3*W - 1

Now substitute to find W:

2* (3*W - 1) + 2*W = 38

6*W - 2 + 2*W = 38

8*W - 2 = 38

W=5

Substitute again to find L:

2*L + 2*5 = 38

2*L = 28

L= 14

So length = 14 m and width = 5 m

Done!

The width is 5 and the length is 14, since the width is w, and the length is 3w - 1, if you add all the sides you get 8w - 2= 38 and solve normally

*Rewrite the given information as expressions.

1. Length = 3x - 1

2. Width = x

*We know the perimeter = 2L + 2W...

2(3x - 1) + 2(x) = 38

First: eliminate parenthesis > distribute the outer terms with the terms in parenthesis (Foil Method).

2(3x) + 2(-1) + 2(x) = 38

6x - 2 + 2x = 38

8x - 2 = 38

Sec: add 2 with boths sides (when you move a term to the opposite side, always use the opposite sign).

8x - 2 + 2 = 38 + 2

8x = 40

Third: solve for "x" by isolating it on one side > divide both sides by 8.

8x/8 = 40/8

x = 5

Now, replace 5 with the "x" varibles to find the values for the Length and width.

1. L = 3x - 1

L= 3(5) - 1

L = 15 - 1

L = 14

2. W = x

W = 5

Solution: 5m by 14m, or 5m x 14m