A question about "if" function on C++?

You probably defined W as integer to get a number from the user. If you put w == c then c is not a number, and also if you put w== "c" it won't compile because w is integer and you are comparing it with a string ("c") so it gives you error.

Explain what you mean by using a letter. Do you mean if i enter 2,3,4 then you print this:

s*2 + 3 + 4

if you mean this, you have to define the first variable as string, like:

string w;

int x,y,z;

then user inputs x and y and z as integers, and w as string.

Explain more what you mean by w being a letter

cheers

As MD stated, && is the logical AND operator. But what are you rather seeking to do right here, and what's x? If x is a bool, then this may increasingly paintings: if(x && y > eight) if x is an int, and you're seeking to see if x and y are each > eight, then you wish to have this: if( x > eight && y > eight)

you have to use ascii values if u want the input as character and not a number then u should check the condition with ascii values

you should type

if(w==3);

you shoud use two "=="

in c++ one "=" means equation not condition.

if w is char you should dim it as char,

for example

{

char w;

if (w=='s')

w='a';

}

Cheers

use "isalpha" - checks if the parameter is a member of the alphabet.

if(isalpha(w))