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Poker Question!?

Would a hand of two Queens, two Sevens, and one Ace beat three Tens, two Sevens and an Ace?

12 Answers

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  • Favorite Answer

    no, 2 queens and 2- 7s is two pair. 3 tens and 2- 7s is a full house. A full house (which is a pair and 3 of a kind) always beats two pair no matter what the two pair are.

  • You have one problem in that the 2nd hand has 6 cards, which is impossible. But the 3 10's beats the 2 Q's and 2 7's. If the 2nd hand also has the 2 7's then it's even better: A full house, which crushes 2 pairs.

    All that being said, is it possible there was a typo in your question. maybe you meant the 2nd hand was 2 10's, 2 7's and an Ace? If so, then the first hand wins (the highest pair in the first hand is higher than the highest pair in the 2nd hand).

  • 1 decade ago

    No, That is 2 pair against a full house. You can't have the ace with the 3 tens and 2 sevens. That is 6 cards, you are only allowed 5.

  • Anonymous
    5 years ago

    Saaammmme Poker

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  • 1 decade ago

    No... 2 Queens with 2 Sevens (and an Ace) is only 2 pair.. When you hold 3 alike cards (trips) with a pair like Sevens.. you get a Full House.

    Below is a link of poker hands and rankings.

  • 1 decade ago

    the seoncd hand cannot have 6 cards, but three of a kind beats two pair anyday

  • 1 decade ago

    No, but the person who has the 10's is cheating. They have 6 cards the other only has 5......

  • Anonymous
    1 decade ago

    I'm not sure what game your refering to, however if you're refering to five card stud or five card draw then two pair beats a full house

  • Anonymous
    1 decade ago

    no. because your opponent has a fullhouse and you only have a 2 pair and oh yeah your opponent has 6 cards you only have 5.

  • 1 decade ago

    no, the first hand is 2 pair. the 2nd hand is a fullhouse

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