math help?

-[-2(x-3)-I-4I]=3x-5

-[-2x+6-4]=3x-5

-[-2x+2]=3x-5

2x-2=3x-5

2x+3=3x

3=x

Ok:

-[-2(x-3) - I-4I] = 3x - 5 (I wasn't sure what I-4I was...if it's modulus then take this value as 4...but I reasoned that if you were stuck on this then you haven't come across that and just took it to be a bracket and to be - 4?)

First expand the bracket -[-2(x - 3) - (- 4)]

The negative sign gives: 2(x - 3) + (- 4) [As – x – = +]

So you now have:

2(x - 3) + (- 4) = 3x - 5

Adding a negative is the same as 'minusing'

2(x - 3) -4 = 3x - 5

Now expand the last bracket

2x - 6 - 4 = 3x - 5

And simplify

2x - 10 = 3x - 5

2x - 5 = 3x

-5 = x

x = -5

And there ya go! =D

(If you're confused about anything in there feel free to e-mail! )

Hope this helped =)

T

EDIT: If |-4| was intentionally modulus then the answer is x = 3...(see posts above)

x=3

X=-42

Here is how it works.

-[-2(x-3)-[-41]=3x-5

First do -2(x-3). That makes -[-2x+6-[-41]=3x-5Then since minusing a negative is the same as adding you have-[-2x+6+41]=3x-5.

Simplify. -[-2x +47]=3x-5

now, in the parenthesis you reverse the signs(since it is negative), so you have 2x-47=3x-5

Now, you minus 2x from the right and left.

-47=x-5

Add 5 to each side. -42=x

Hope this helps.

p.s. The answer is not 3. instead of x i will put in the 3 for x.-[-2(3-3)-(-41)]=9-5

Also, I can not tell if it is -1-41 or -[-41] either way x is not three. try it yourself.

-[-2(x-3) - I-4I] = 3x - 5

-2(x-3) - I-4I = 5-3x

-2x+6 - I-4I = 5-3x

- I-4I = - 1-x

I-4I = 1+x

x=3

-[-2(x-3) - I-4I] = 3x - 5

-[-2x+6-1-41] = 3x - 5

-[-2x - 36] = 3x - 5

2x +36 = 3x - 5

41 = x

Um. I got x = -3/5. But, I could be wrong.

-[ -2(x-3)-l-4l]=3x-5

-[-2x+6-4]=3x-5

-[2x+2]=3x-5

-2x-2=3x-5

-2x=3x-3

-5x=3

x=-3/5

It doesn't seem right. But, I tried. Sorry.

2x-2 = 3x-5

x=3

-(-2x+6-4)=3x-5

2x-2=3x-5

-2+5=3x-2x

3=x

x=3