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Need the formula for an ellipse containing a specific (x,y) with axis ratio of 1.355?
I'm working on a legacy program at work and could use some help.
I am drawing an ellipse that always has an x-axis that is 1.355 times that of the y-axis. The ellipse also passes through a specific (x,y) coordinate. I can figure out the displacement so assume that the origin is the center of the ellipse.
Can anyone help? It's been more than a year since my last math course and I've forgotten everything, apparently.
2 Answers
- Kathleen KLv 71 decade agoFavorite Answer
you can use x² / a² + y² / b² = 1
where a = 1.355b
thus, a² = 1.836b²
So you have an equation with b in it (in addition to the x and y). You can solve for b by plugging in the coordinate you know.
- Dr DLv 71 decade ago
The general formula of an elipse is
[x-C1]^2 / a^2 + [y-C2]^2 / b^2 = 1
C1, C2 is the center
a = x width
b = y width
