Help! Im stuck with a math question!!?

You have to multiply it out.

(x+h)(x+h)(x+h)

So, do (x+h)(x+h) first

which equals: x^2 + 2xh + h^2

then do (x^2 + 2xh + h^2)(x+h)

which equals: (x^3 + x^2h +2x^2h + 2xh^2 +xh^2 + h^3)

then you just combine similar variables:

= x^3 + 3x^2h + 3xh^2 + h^3

Make sense?

If you forgot the special factors for (x+h)^3, simply multiply (x+h) three times by itself.

Like : (x+h)(x+h) = x^2 + 2xh + h^2

(x^2 + 2xh + h^2)(x+h) = x^3 + 2x^2h + xh^2 + x^2h + 2xh^2 + h^3 = x^3 + (2x^2h + x^2h) + (xh^2 + 2xh^2) + h^3

= x^3 + 3x^2h + 3xh^2 + h^3

foil the first out to get x^2+2xh+h^2 then multiply each of those by x to get x^3+2x^2h+h^2x and by h to get x^2h+2xh^2+h^3 to get x^3+3x^2h+3xh^2+h^3

or pyramid

1

11

121

1331

(x+h)^3 = (x+h)*(x+h)*(x+h) = [ (x+h)^2 ] *(x+h)

(x+h)^2 = x^2 +2xh + h^2

(x+h)^3 = [ x^2 +2xh + h^2 ] * (x+h)

= (x^3+3x^2h+3xh^2+h^3).

I guess you skipped algebra 2 and precalc to go into calculus ;-)

(x+h)^3 = (x+h)(x+h)(x+h) = (x+h)(x²+2xh+h²)

distribute these and you will have the cubic expansion shown in your question

Just memorize that one as well as (x+h)² because that is used all the time when working with the definition of the derivative in calculus