First person right gets 10 points!!!?

a)

b - 13 < 2b + 10

subtract 2b on both sides

b - 2b -13 < 2b - 2b + 10

-b - 13 < 10

add 13 on both sides

-b < 23

multiply both sides by (-1) [by multiplying by (-1), the inequality sign changes!]

b > -23

_____________

b)

- 5 (x+2) < -2 -5x

-5x -10 < -2 - 5x

add 5x on both sides

-10 < -2

This is trivially true (true for any x, independent of x)

=> all real numbers x are the solution

____________

c)

3x + 3 > -3

subtract 3 on both sides

3x > -6

divide both sides by 3

x > -2

_________

Hope this helps!

First person right gets 10 points!!!?

Can u plz help me w\ solving inequlaities?!?!?!?

a) b-13<2b+10 subtract b+10 from each side

-23<b or

b>-23

b)-5(x+2)<-2-5x distribute -5

-5x-10<-2-5x add 5x to each side

-10<-2 true for all x

c)3x+3>-3 subtract 3 from each side

3x>-6 divide both sides by 3

x>-2

a)

b-13<2b+10 ==> -13 - 10 <2b - b ==> -23<b

b)

-5(x+2)<-2-5x ==> -5x -10 < -2 -5x ==> -5x +5x <-2+10

==> 0<8

it's obvious

c)

3x+3>-3 ==> 3x>-3-3 ==> 3x > -6 ==> x>-2

M is right, but there is more than one way to do math see below.

a) b-13<2b+10 substract b from both sides

-13<b+10 substract 10 from both sides

-13 + -10 < b

-23 < b

b)-5(x+2)<-2-5x expand -5(x+2)

-5x-10<-2-5x add 5x to both sides

-10<-2

c)3x+3>-3 subtract 3 from both sides

3x > -6 divide by 3

x> -6/3

x>-2

well, the first and second one i don't get but i can help u with the third one okay so this is how you do the third one

so it is 3x+3>-3

so first u have to get rid 3 so u have 2 subtract 3 from both sides...

so now it's just 3x>-6

now divide both sides by 3

so it's x>-2

a.b-23<2b+10

b>-23

b.-5x-10<-2-5x

0x>8 no answer

c.3x+3>-3

3x>-6

x<-2

a) -3<b

b) the x' are cancled out you have -10<-2

c)x>0

HA HA HA! I almost failed my 7th year because of those!

its A