Help with distance word problems?

60T=30(T+2)

60T=30T+60

30T=60

T=2 hours

At the time when Bubba catches her, their distances will be equal. Their distances can be expressed as Rate*time, with Bubba's time 2 hours less than Aphasia's time. So we have the following:

Aphasia's distance = 30T

Bubba's distance = 60(T-2)

Therefore,

30T = 60T-120

T = 4, which is 4 hours after 9 a.m., or 1 pm

12:30 PM

By the time Bubba left Aphasia was 60 miles away from "START" one hour later Bubba was 60 miles away from "START" and Aphasia went another 30 miles so she is 30 miles away more from Bubba 30 minutes later Bubba went 30 miles and Aphasia met Bubba because he is going twice as fast and she doesnt go farther.

at 1 p.m. aphashia would have gone 120 miles because 4 hours at 30mph is just 4*30 and bubba would also have gone 120 miles because 2 hours at 60 mph you times 60 by 2 so they would meet at 1 p.m.

I don't know how to put subscripts here, so if it says v1 or d2, assume the number is below the line.

d1 = d2

v1t1 = v2t2 (if car 2 travels t hours, car 1 travels t+2 hours)

(30mph)(t+2) = (60 mph)t

30t + 60 = 60t

30t = 60

t = 2 hours

The second car will travel 2 hours. Therefore, the second car will reach the first one at 1 p.m. =]

1P.M.

By 11 a.m Aphasia has gone 60 miles so

60 +30t =60t when they catch up where t is time in hours after 11 a.m.

What would "X" be in your equation? Which hands of the clock? If you are talking about the minute and hour hands, this problem can be set up as a D = RT problem, but the motion is rotary, involving radians, not straight-line miles! As another answer states, just use your brain! The minute hand makes a complete circle every hour, so the answer has to be "less han an hour". As for when, it really depends upon the clock. In a "perfect world", the minute hand moves 360 degrees in an hour while the hour hand moves 360 degrees in twelve hours! If "X" is the rate of the minute hand, then X/12 is the rate of the hour hand! They will be together when the (Original Location + D = RT) are equal. Set the rest up yourself.

http://en.wikipedia.org/wiki/how_to_solve_it

x is the hours traveled.

30x = 60(x-2) x is the time Aphasia traved

x-2 is the time Bubba traveled; when they meet they are equal.

30x = 60x -120

-30x = -120

x = -120/-30 = 4 hours; 9AM+4 hours

= 1PM

about like 1 o clock pm

how to find

u noe that at 11 am wud b at 90miles for the aphashia guy so then at 1 o clock it would be

120miles

steps:

APHASHIA:

9o clock: 0miles

10 o clock: 30miles

11o clock : 60 miles

12 o clock: 90miles

1 o clock PM: 120 miles

BUBBA:

11 o clock: 0 miles

12 o clock: 60 miles

1 o clock PM: 120 miles

1 o clock is the same time they at the same miles

so tecnically u add the amount of miles they going at to the current miles like shown above(sorta) =)

1 p.m.