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Help with Math B question?
I have my math B regents tomorrow and my friend and I can't figure out how to do this one problem. It's problem #20 on the NYS June 2005 regents exam (you need to scroll down and find the exam. The link from the exam doesn't work). http://www.nysedregents.org/testing/mathre/regentm...
From there, you have to scroll down to the 6th page and its question #20.
Could you please include a detailed explaination? Thanks!
5 Answers
- 1 decade agoFavorite Answer
http://schools.nycenet.edu/d75/HIS/shack/mathemati...
has step by step answers to that question
Source(s): its great, i used it - ≈ nohglfLv 71 decade ago
Remember that
sine = opposite/hypotenuse
From looking at the coordinates on the picture
we can determine that the circle is a unit circle.
All radii in the circle are equal to one.
Using that segment QO is a hypotenuse that has length one
Segment QS/ QO = QS
Segment PR can't work because it corresponds to hypotenuse PO which is greater than one
So PR couldn't be sin(theta) on it's lonesome
The answer is segment QS(4)
- 1 decade ago
I'm going to substitute angle a for theta...
sin a = sin (180-a)
sin a = PR/RO
RO = 1
sin a = PR
Answer 3 is correct.
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