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Al asked in Science & MathematicsMathematics · 1 decade ago

Pretty Easy Math Question?

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A rectangular pool has a width of 10 feet and a length of 20 feet. The deck that surrounds the pool is 2 feet wide. What is the area of the deck that surrounds the pool.

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  • 1 decade ago
    Favorite Answer

    Mr Buttface: let me provide assistance.

    Rectangular pool: area = length*width

    area = 10* 20 = 200 sq ft

    if the deck is two feet wide (draw this so can visualize it), the length is now 2+10+2 = 14 ft

    width is now 2+ 20+ 2 = 24 ft

    area of the deck is Total area - Pool area

    = 14*24 - 200

    = 336 - 200 = 136 sq-ft

  • mark
    Lv 6
    1 decade ago

    pool width = 10'

    pool length = 20'

    deck 2' wide

    one method is to work out the total area enclosed by the deck and subtract the area of the pool

    so deck length = 20 + 2 + 2 = 24 deck 2' each end

    deck width = 10 +2 + 2 = 14 deck 2' each side

    deck area = (24 x 14) -( 20 x 10) area of deck - area of pool

    deck area = 336 - 200 = 136 sq feet.

    ***************************

    another way

    4 sections of deck plus the 4 corners

    (2 * 20 *2 ) +(2 * 10 * 2) + ( 4 * 2 * 2 )

    pool length (sides) + pool width (ends) + corners

    = 80 + 40 +16

    = 136 sq feet

    *****************************

    easiest with this is to draw it on a piece of paper, and mark the rectangles that make up the deck.

  • 1 decade ago

    First you determine the perimeter of the pool including the deck. 2(20 + 2) + 2(10 + 2) = 68. Multiply the perimeter of the pool + deck times the width of the deck. this is 68 x 2 = 136. So the area of the deck is 136 sq. ft. Hope this helps.

  • 1 decade ago

    First find the area of pool:

    A=LxW

    A=20x10

    A=200 f^2

    Next find the area of the pool with the deck:

    A=LxW

    A= 24x14 (add 4 feet to each measurement since the width of the deck is 2 feet and it surrounds the entire pool)

    A=336 f^2

    Now subtract the area of the pool and deck from the area of the pool itself:

    336 – 200 = 136

    Therefore the deck is 136 feet squared.

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  • 1 decade ago

    the area of the pool (2-D) is length times width which is 10 times 20 which is 200 feet squared.

    if the deck extends from the pool 2 feet then the width of the deck is 24 ft and the length is 14 feet. 24 times 14 is 336 feet squared. since you are only wanting the area of the deck, look at it like a picture fram. there is the outter rectangle and the inner rectangle. if you want the area between the outter and inner rectangles then subtract the area of the smaller rectangle from the area of the larger rectangle. so you will be looking at 336 feet minus 200 feet. and the area of your deck is 136 feet squared.

    hope this helps!

  • Anonymous
    1 decade ago

    add the width of the pool(10 feet) to the 2 feet wide of the surrounding deck (2 feet)

    this will give you 12 feet x 20 feet, thats the formula for def do that and get ur answer but cant work it out without calculator cos ive had a few wines xxx

  • 1 decade ago

    pool= 10 ft, + 2 ft of decking either side = 14 ft wide.

    Pool = 20 ft long, + 2 ft decking either end = 24 ft.

    Area of pool + decking = 14 x 24 = 336

    Minus the azrea of the pool (10 x 20 = 200)

    = area of decking = 136ft

  • 1 decade ago

    You need to learn how to do this....

    The areas are width x length.

    The width of the largest area is 10 + 2 + 2 = 14 feet

    The length of the largest area is 20 + 2 + 2 = 24 feet.

    Subtract the largest area from the smallest area, and you'll find your solution!

    Good luck :)

  • 1 decade ago

    Area = 14(24) - 200 = 136 ft^2

  • 1 decade ago

    Basically, you have a strip of concrete 2 feet wide, and the length is the distance of the perimeter (distance around the pool). the perimeter is twice the length + twice the width (10+10+20+20) or 60 feet. Then your square footage is just 60 feet X 2 feet or 120 square feet.

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