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Arithmetic Sequence Question?
Here is a problem from my text book that i cant figure out for the life of me.
"Find the value of y that makes y+8, 4y+6, 3y...an arithmetic sequence"
HELP!
3 Answers
- 1 decade agoFavorite Answer
4y+6 - (y+8) = 3y - (4y+6)
4y+6 - y -8 = 3y -4y - 6
3y - 2 = - y - 6
4y = -4
y = -1
example
a, 2a, 3a
the difference, d in the arithmetic seq can be found by
substracting 1st term from the 2nd term
3a - 2a = 2a -a
- EllisLv 61 decade ago
y=-1
For an arithmetic sequence the difference in terms is the same, say x
Therefore (y+8)-(4y+6)=x and (4y+6)-3y=x
solving both equations gives y= -1
Check
y+8=7, 4y+6=2, 3y=-3 and the constant difference between terms is 5
- Anonymous1 decade ago
[(y + 8) + 3y]/2 = 4y + 6
4y + 8 = 8y + 12
-4 = 4y
-1 = y
7, 2, -3
