any one please solve this question for me?

I won't anser the question but will tell you how to do it:

Put the equations in the form y = mx+b

m= slope = delta y / delta x

b = y intercept or where the graph crossed the y axis

For perpendicular lines, m1 = -1 / m2 or in other words the slope of the first line is the negative reciprocal of the slope of the second line.

you need to solve both for y

the first one becomes y=2x-5 and the second one becomes y=-(1/2)x+(1/2)

then you look at the slopes

the first slope is 2 and the second slope is -(1/2)

these two slopes are the negative reciprocals of each other which means the lines are perpindicular

I hope that helps

the first equation is ( y-1)/2= x-3

which, in terms of y = mx + b

y = -(1/2)x + 1

the second one

8-2y = x+7

in terms of y = mx + b

y = 2x - 7

the slopes are

(-1/2)x and 2x

if you do (2x)^-1....it is 1/2x

so they are perpendicular

For parallel lines M1 and M2 are equal.

If no relation is found...none of these would be your answer.