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Probability?
If an art museum had 6 places to hang 11 paintings how many different exhibits could the museum put on display?
The answer is supposedly 2,772, but i dont see it at all.
Using the Combination formula, I got 462, time and time again.
Thanks for your help!
2 Answers
- parspantsLv 51 decade agoFavorite Answer
462 is the answer if we suppose that the order of the paintings doesn't matter. I'd say it doesn't and you're right.
If it DOES matter, however, the binomial theorem gives 332,640 combinations, so I'm going to say that the 2772 solution is, as they say on car-talk, booooogus.
I suppose they may argue that they don't have to hang six paintings at all, but may choose to exhibit 3 or 5 or something like that, but good grief! That doesn't seem like a fair question to me.
- 1 decade ago
I found out that 2772 = 462 x 6 = 11C6 * 6... Perhaps you are missing an information or the "supposed" answer is wrong.
