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Math Help? Explain.?
Which of the following can't be lengths of a triangle?
1. 1 2 4
2. 3 4 6
3. 4 5 7
4. 5 6 8
The ratio of the C of 2 circles is 4 to 1. What's the ratio of the area of the 2 circles? (simplified)
The sum of digits of a certain whole # is 7. What is the least possible value of the sum of the digits of the # which is 300 more than the original #?
1
8
10
307
3 Answers
- hayharbrLv 71 decade agoFavorite Answer
The two shorter lengths must add up to more than the longest length so 1,2 4 wouldn't work
The ratio of the areas is the square of the ratio of the circumference since area is in square units but C isn't.
So 4^2 to 1^2= 16 to 1
Its's 10. Say the number is 25 then 300 more is 325 and 3+2+5=10
- Anonymous1 decade ago
the 1st one is 1, because the 2 smallest sides cannot be bigger than the largest in a triangle.
i dont know the middle one.
i think that the last 1 is 307, but i am not 100% sure.
- ironduke8159Lv 71 decade ago
1 2 4 because1+2 not greater than 4
c1 = 2pir1
c2 = 8pir2
Soc2/c1 = 4/1 = r2/r1 --> r2= 4r1
A1 = pi r1^2
A2 pir2^2 = pi (4r1)^2 = = 16pi r1^2
So A2/a1 = 16
10
The numbers are 16 and 316
