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Find the general solution of the differential equation. (dy/dx) -2xy = (3x^2)^(x^2) ; y(0) =5?

I know how to differentiate implicitly down to y(e^-x) = integral[(e^-x)((3x^2)^(x^2))]dx but I don't know how to do this integral. Please help...thanks

28 Answers

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  • 1 decade ago
    Favorite Answer

    You are correct that the solution contains an integral (I used Maple to solve the ODE), but your integral is incorrect. The correct integral is this:

    ∫[(3^(x^2)) * (x^2)^(x^2)] / x dx

    As for evaluating the integral, I believe that this type of integral does not have a closed form solution.

    I am in disbelief of how many people gave dumb answers to this question.

    edit:

    Here's a thought on the integration:

    ∫[(3^(x^2)) * (x^2)^(x^2)] / x dx

    Let u = x^2

    du = 2x dx

    dx = du / (2x)

    = ∫[(3^(u)) * (u)^(u)] / 2u dx

    = (1/2) ∫[(3^(u)) * (u)^(u-1)] dx

    Well, this is still not integrable.

    I would leave your solution in this form:

    y = ±sqrt(-∫ [(3^(x^2)) * (x^2)^(x^2)] / x dx + C)

  • Dr D
    Lv 7
    1 decade ago

    Like whitesox said, there comes a point where you just can't get a closed form solution. The (3x^2)^(x^2) is awfully tough to integrate.

    But where did all these people come from. You have no contacts.

  • 1 decade ago

    9

  • 1 decade ago

    i dont know that one but....

    M145 Sample Quiz #1 April 01, 2004

    (1a) Find

    dy

    dx

    for y = x ln(x2 + 3).

    (1b) Find

    dy

    dx

    for y =

    1

    1 + e2x .

    (2) Let y = f(x) = 6x − x2 + 5, for 1  x  6. For which values of x is f(x) increasing?

    decreasing?

    For which values of x is f(x) concave upwards? concave downwards?

    What are the maximum and minimum values of f(x) (for 1  x  6). Then sketch f(x) (for

    1  x  6) .

    10

    (3) Suppose xy2 + xy + 2 = exy. Calculate

    dy

    dx

    at the point (x, y) = (0, 2).

    (4) Let y = f(x) = x3 −

    3

    2

    x2 − 6x + 3. Find f0(x) and f00(x).

    (4a) At which points x is f0(x) = 0?

    On which intervals of the x axis is f(x) increasing?

    On which intervals of the x axis is f(x) decreasing?

    (4b) On which intervals of the x axis is f(x) concave up?

    On which intervals of the x axis is f(x) concave down?

    (4c) What are the maximum and minimum values of f(x) for −3  x  3.

    (4d) Sketch f(x)

    −3 3

    −10

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  • Anonymous
    1 decade ago

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    The international scientific-educational website EqWorld presents extensive information on solutions to various classes of ordinary differential, partial differential, integral, functional, and other mathematical equations. It also outlines some methods for solving equations, includes interesting articles, gives links to mathematical websites and software packages, lists useful handbooks and monographs, and refers to scientific publishers, journals, etc. The website includes a dynamic section Equation Archive which allows authors to quickly publish their equations (differential, integral, and other) and also exact solutions, first integrals, and transformations.

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    ^-x)((3x^2)^(X1-45)

    Physics Today, July 2005, p. 35

    =

    )^(x^2) ; y(0) it equals 9

  • Hey, I know a website that will have the answer, but I doubt your computer will let you get to it. My computer restricts it! I don't know if yours will. Maybe my mom put parental controls on my computer. I don't know why! It's a math website! OK!

  • Anonymous
    1 decade ago

    its asking for x find, plug y =0 which means 0=(3x^2)^(x^2) solve for x

  • 1 decade ago

    this is an expl.

    3-4(7x8)=

    (7x8) must go first

    56

    then

    3-4=neg 4

    neg 4x56=224

  • 100,000,000,002. I don't know, really. That's just a cool number. The problem looks impossible to me. Sorry!

  • 1 decade ago

    (dy/dx) -2 ; y(0) =5?dx) -2 ; y(0)

    ; y(0) =5?xy = (3x^2)^(x^2[(e^-x)

    ((3x^2)^(x^2= (3^2)^(x^2[(e

    -2 ; y(0) =5?dx) -2 ; y(0) ; y(0) =

    5?xy = (3x^2)^(x^2[) ; y(0) =5?xy

    = (3x^2)^(x^2[(e^-x)((3x^2)^(x^2=

    (3x^2)^(x^2[(e-2 ; y(0) =5?dx) -2

    ; y(0) ; y(0) =5?xy = (3x^2)^(x^2[

    ) ; y(0) =5?xy = (3x^2)^(x^2[(e^

    -x)((3x^2)^(x^2 = (3x^2)^(x^2[(e

    -2 ; y(0) =5?dx) -2; y(0) =5?xy =

    (3x^2)^(x^2[(e^-x)((3x^2)^(x^2

    = (3x^2)^(x^2[(e-2 ; y(0) =5?dx)

    -2 ; y(0) ; y(0) =5?x

    Source(s): i'm a genius!!!!!!!!!!!!!!!!!!
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