A college basketball game was attended by 1243 people. Student tickets cost $2 and all others cost $8. The?

It depends what division this is. I would assume that NCAA would have raked in significantly more revenue though. Oh well, perhaps they were in the losing end of the season.

You need to write two equations and substitute.

S + O = 1243

2S + 8O = 5018

O = 1243 - S

2S + 8(1243 - S) = 5018

2S + 9944 - 8S = 5018

6S = 4926

S = 821

student tickets = s adult tickets = a s + a = 600 1.5*s + 2.5*a = 1020 multiply first line by 1.5 to make s equal in both equations 1.5s + 1.5a = 900 1.5s + 2.5a = 1020 subtract the first line from the second one a = 120 sub it back into the original equation of s + a = 600 s + 120 = 600 s = 480 student tickets = 480 adult tickets = 120

x=number of students

y=number of others

2*x+8*y=5018

x+y=1243

x=1243-y

plug this into the first equation for x

2*(1243-y)+8*y=5018

2486-2y+8y=5018

2486+6y=5018

6y=2532

y=422

x+y=1243

x+422=1243

x=821

5018=2x+8x(1243)

5018=10x(1243)

-1243 -1243

3775=10x

-----_______-__

3775 divided by 10 equals 377.5

answer: 377.5

y = # of students

x = # of others

1) 2y + 8x = 5018

2) y + x = 1243 -> 3) y = 1243 - x

sub. 3 into 1

2(1243-x) + 8x = 5018

solve for x.

sub. wat u get for x into 2

y + x = 1243

here u will get the value for y.

Result

U have the x and y values and look at wat i wrote on the top.

how many non students attended?

399?

What college?

2486