4|x+3|-16=20?

First, add 16 to both sides to get

4|x + 3| = 36. Now divide by 4.

|x + 3| = 9. And |x + 3| = -9.

x = 6. x = -12.

Answer: choice C.

-John

First add 16 to both sides of your equation.

4|x + 3| - 16 + 16 = 20 + 16

4|x + 3) = 36

divide by your coefficient of your absolute value term:

4|x + 3|/4 = 36/4

|x + 3| = 9

then x + 3 = +/- 9

if x + 3 = +9 then x = 6 (subtracting 3 from both sides)

if x + 3 = -9 then x = -12

You may check these solutions by substituting for x:

4|6 + 3| - 16 = 20

4|9| - 16 = 20

36 - 16 = 20

20 = 20

or

4|-12 + 3| - 16 = 20

4|-9| - 16 = 20

since absolute value of -9 is 9 you have

4(9) - 16 = 20

36 - 16 = 20

20 = 20

your correct answer choice is "c"

c, X=6.

4(X+3)-16=20

4(6+3)-16=20

4(9)-16=20

36-16=20

simple

c)x=6 or x=-12

4|x+3|-16=20

4|x+3|=20+16

4|x+3|=36

|x+3|=9

x=9-3 or x=-(9+3)

x=6 or x=-12

4(x+3) -16 = 20

4x + 12 - 16 = 20

4x - 4 = 20

4x = 24

x = 6

therefore, the answer is C.

4|x+3|=36

So |x+3|=9

So x+3=9 or x+3=-9

So x=6 or x=-12

-4x-12-16=20

-4x-28=20

-4x = 48

x = -12

or

4x+12-16=20

4x-4=20

4x=24

x=6

the answer is c

| x + 3 | = 9

(x + 3) = 9 or (x + 3) = - 9

x = 6 or x = - 12

OPTION c)

Choice C I just did it on some scratch paper

C