College Algebra-Factor x^4-16=?

(x² - 4)(x² + 4)

(x - 2)(x + 2)(x² + 4)

Difference of two squares, hence (x^2-4)(x^2+4). But the first of these factors is also the difference of two squares, so the final result is (x-2)(x+2)(x^2+4).

-2, or +2

The answer to your question is:

x = 2 or x = - 2

add 16 to both sides then take the 4th root of 16. using the positive and negative.

(x^2 - 4) (x^2 + 4)

(x^2-4)(x^2+4)

*question

please dont get offended. Im on 7th grade and taking honors alg 1. and u r doing college algebra? seriously?

Difference of squares. (x^2-4)(x^2+4)

Going further, (x-2)(x+2)(x^2+4)

difference of squares

(x^2 + 4)(x^2 - 4)

-16

it is (x^2-4)^2

but even that is factorable

so you simplyfy it even more

(x-2), (x-2), (x+2) (x+2)

then u simplify, and then u get

(x-2)^2, (x+2)^2

i took the test yesterday, got a hundred!

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