The LAST one! math help one question!?

since they are equal

2x+11=4x+5

then you have to figure out what "x" is

2x+11=4x+5

-2x -2x (have "x" on one side and by itself)

11=2x+5

-5 -5

2x=6

/2 /2

x=3*

then you plug it into the equation for segment AB [ 4x+5 ]

4(3)+5

12+5

*17* [the measurement of AB]

Cool problem!

First, recognize that the perpendicular bisector, segment AD, makes segment BD = BC. From there, we can say that triangles ABD and ADC share 2 sides of the same length, including that segment AD. Knowing the properties of triangles, segments AB and AC absolutely MUST equal each other.

Now we have to do some algebra. Set the two equations for AB and AC equal to each other.

4x+5 = 2x+11

Now subtract 5 from each sides

4x = 2x+6

Subtract 2x from each side.

2x = 6

Divide each side by 2.

x = 3

We have to find the measure of segment AB, who's equation is 4x+5. So all we have to do is plug in x=3.

4(3) + 5

= 17

AB = 17

Given information: Segment AD is a perpendicular bisector of triangle ABC.

Given information (from the image): Segment BD is congruent to Segment DC.

So, since Segment BD and DC are congruent, and Segment AD and AD are congruent, then that means- by the Side-Side-Side Theorem- that Segments AB and AC are congruent to one another.

WORK:

AB = AC

4x + 5 = 2x + 11

2x + 5 = 11 [Subtract 2x from both sides of the equation]

2x = 6 [Subtract 5 from both sides of the equation]

x = 3 [Divide 2 by both sides of the equation]

Given: x = 3

WORK:

To find the measure of segment AB, use the given information above (x = 3) and substitute it for AB's equation (4x + 5)

AB = 4x + 5

= 4(3) + 5 [Substitute 3 for x]

= 12 + 5 [Multiply 4 and 3]

AB =17

If it's a perpendicular bisector, then the two small triangles have one angle in common (the 90 degree angle) and they have two sides equal (they have AD in common, and the length of DC = length of DB). Thus the two triangles are congruent, which means that the length of AB = length of AC.

So 4x+5 = 2x+11.

Solve this equation to find x, then find the length of AB (which is 4x+5).

The diagonal AC divides the parallelogram into 2 congruent proper triangles--CAB and ACD. CAB is a suitable triangle with BC the hypotenuse. (AC)² = (BC)² - (AB)² = 13² - 12² = 169 - one hundred forty four = 25 AC = 5 Calculate the area of triangle CAB. area = ½bh = ½*AC*AB = ½*5*12 = 30 Triangle ACD is congruent to triangle CAB so the area of the parallelogram ABCD is: 2*30 = 60 cm²

The two legs are of equal value because AD is an angle bisector that means that the two halves of the base are congruent so simple triangle congruence shows that the legs are equal. Quite simple.

AC=AB

2x+ 11= 4x +5

-2x , -5 (from both sides)

6= 2x

x=3

AB= 4(3) +5= 17

i haven't done this in a while but i think it's correct

if it is a perpindicular bisector then it will split the triangles with a 90 degree angle, so you need to do the equasion using Sin Cos Tan SOHCAHTOA

since ad bisects it cuts it into 2 (hence the suffix bi-) equal parts meaning both ab and ac are equal so: 4x + 5 = 2x + 11......get variables on one side: 2x = 6.....so: x = 3

i hate math