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equalities and inequalities help!!!?
Sales, given in thousands, for a particular company in 1990 were at 120.5 and in 2000 at 140.5, estimate the sales for the years 1997 and 2003. Let x = 0 correspond to 1990. Using the distance formula, find the approximate distance between the values in 1997 and 2003. Explain the difference between using the distance formula and simply subtracting the two estimated values.
1 Answer
- ?Lv 71 decade agoFavorite Answer
You have 2 points for a graph; (1990,120.5) and (2000,140.5)
The instructions tell you to use the origin as 1990
x=0 therefore corresponds to (0,120.5) and (2000,140.5) would be the
same as (10,140.5)
Let's find the equation for the line that joins the 2 points.
The equation will take the form y=mx+b, where m is the slope of the line and b is the y-intercept..
Slope = m= rise/run, =(y2-y1) / (x2-x1)
m= 140.5-120.5 / 10-0
=20/10
=2
So y=2x+b
Pick either of the 2 given points to use in finding b. I'll use (0,120.5)
y=2x+b
120.5=2(0)+b
120.5=b
Our equation is now fully known . It is y=2x+120.5
Now, let's find the required estimated values.
At 1997, x=7 (since 1990 occured at x=0, 1997 is 7 away from 0).
y=2(7))+120.5
y14+120.5
y=134.5
At 2003, x=2003-1990, =13
y=2(13)+120.5
y=26+120.5
y=146.5
1997, 134.5 sales, in thousands
2003, 146.5 sales, in thousands
The Distance Formula is simply the Pythagorean formula, nothing more.
D^2= (y2-y1)^2+x2-x1)^2
D^2= (146.5-134.5)^2 +(2003-1997)^2
D^2=12^2+6^2
D^2=144+36
D^2=180
D= 13.42 units
Subtracting the 2 estimated values is y2-y1
=146.5-134.5
=12 units
The difference between the 2 answers is due to the fact that the
Distance Formula measures the length of the hypotenuse of the
triangle formed by the 2 given points, whereas the subtraction of the
2 y values measures one side of the right triangle.
The subtraction method is correct, since it calculates the change in
sales for 6 years, The Distance formula does not.