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Calculus: Rates of change...?
A spherical snowball is melting. Its radius is decreasing at 0.2cm per hour when the radius is 15cm. How fast is its volume decreasing at that time?
can someone show me how to solve this? i'm having a lot of trouble with section and these types of problems.... :(
1 Answer
- bellisiLv 41 decade agoFavorite Answer
Let r be the radius, V be the volume.
Given at r = 15 cm, dr/dt = 0.2 cm/hr
V = (4/3)(pi)r^3
dV/dt = (4/3)(pi)[3r^2(dr/dt)]
Plug in r and dr/dt:
dV/dt = 4(pi)[(15cm)^2](0.2cm/hr)
=24pi cm^3/hr
sorry don't have a calculator on hand to multiply 24 by pi
