Help with a math problem? Not sure what type of math?

a little less than a year quit flunking and work!

There are 12 months in a year, so let's number them first.

January 1

February 2

March 3

April 4

May 5

June 6

July 7

August 8

September 9

October 10

November 11

December 12

Ok so now we know the order. Melissa was born at the start of march, 1987. Kaitlyn was born near the end of may of 1986. We can start with Kaitlyn's birthday and count forward.

May-June-July-August-September-October-November-December-January-February-March.

Now we can see that Melissa is around 10 months younger than Kaitlyn. But, if we average 30 days a month and subtract the 22 days after the start of may Kaitlyn was born we will know how many days were left in may between the two birthdays. Now we can add the four days in march Melissa was born after the first to get 12 days between the two. But, now we have to subtract a month to account for those lost days in may.

Kaitlyn is 9 months and 12 days older than Melissa. I hope that helps!

Jan

Feb

March

April

May <-Kaitlyn 1986

June

July

August

September

Oct

Nov

Dec

Jan

Feb

March <-Melissa 1987

April

May

June

July

August

September

Oct

Nov

Dec

There are 31 days in May, and 31 days in March

31 - 22 = 9days

9days + 4days = 13days

There are 9 MONTHS apart from May1986 and March 1987

THEREFORE Kaitlyn is 9 months and 13days older than Melissa

http://www.timeanddate.com/date/durationresult.htm...

Duration calculation results

From and including: Thursday, May 22, 1986

To, but not including : Wednesday, March 4, 1987

It is 287 days from the start date to the end date, including the end date

Or 9 months, 11 days including the end date, or 41 weeks (using only 30 day months, however)

The way I figure differences is to first see how many days are left in one month to the first of the next (May 22 to May 31=9* days); June 1 to Jan. 31=7 mon. 31 days OR 8 mon ; Feb. 1 to March 4=32 days, which equals yet another month + 1* day. So you have 9 months and 10* days )

kaitlyn is 10 months and 13 days older

It's clear, She's (365 - 78) = 287 days older.

1987 is not a leap year so it'll count as 365 days.

in the previous we start up bear in mind: what you do on one area of the equivalent sign you besides might might desire to do on the different and a damaging selection divided via a damaging selection makes a favorable selection so the point is to get x via itself.. First you subtract 6 from the two sides. you will then have -2x = -26 (because you subtracted 6 from the two sides). after which you divide -2x via -2 so which you will have only x. then divide -26 via -2 and you gets 13. so interior the tip you would be wanting x= 13 and thats your answer

9 months and 10 days older or 11 days on a leap year

March 4,1987

-may 22 1986

9 months,9 days:)

9 months and 12 days

10MONTHS 18DAYS OLDER

START COUNTING FROM 5-22-1986 TO 3-4-1987.

IT'S 10 MONTHS, THEN 22-4=18

1986-JUNE

JULY

AUGUST

SEPT.

OCT.

NOV.

DEC.

1987-JAN.

FEB.

MARCH

THIS IS THE RIGHT ANSWER.